In △BAC, Angle BAC= 90°, segment AD, seg BE and seg CF are medians. Prove: 2(AD²+BE²+CF²)=3BC² Get link Facebook Twitter Pinterest Email Other Apps September 30, 2018 Get link Facebook Twitter Pinterest Email Other Apps Comments
In the adjoining figure, AD is the bisector of the exterior angle A of triangle ABC. Seg AD intersects the side BC produced in D. Prove that: BD/CD=AB/AC. September 30, 2018 Read more
In triangle ABC, Angle ACB=90°, seg CD is perpendicular to seg AB, seg DE is perpendicular to seg CD. Show that: CD² x AC = AD x AB x DE. September 30, 2018 Read more
Comments
Post a Comment