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Showing posts with the label Circles

Two concentric circles with center O, seg AB, seg BC are the tangents to the smaller circle at point P, Q and R respectively and also they are chords of the bigger circle. Prove that : Seg PQ is parallel to seg AC, PQ = (1/2)AC.

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If four tangents of a circle determine a rectangle then show that it must be a square.

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In the adjoining figure, AB is a diameter of a circle with center O, Seg AC is a tangent to the circle at point A. Line JD touches circle at point D, and intersects segment AC in point J. Prove that: seg AJ ≅ seg CJ

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In the adjoining figure, line AP is a tangent to a circle with center O at point A. Seg AF is angle bisector of ∠BAC. Prove that: seg AP ≅ seg PE

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The bisectors of the angles A, B of △ABC intersect in I, the bisectors of he corresponding exterior angles intersect in E. Prove that ▢AIBE is cyclic.

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From the end points of a diameter of circle perpendiculars are drawn to a tangent of the same circle. Show that their feet on the tangent are equidistant from the center of circle.

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Two circles with center O and P intersects each other in point C and D. Chord AB of the circle with center O touches the circle with center P in point E. Prove that: ∠ADE + ∠BCE = 180°

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Show that the radius of incircle of right angled triangle is equal to the difference of half of the perimeter and the hypotenuse.

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△ABC is an equilateral triangle. Bisector of Angle B intersects circumcircle of △ABC in point P. Prove that CQ = CA

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If two circles are internally touching at point P. A line intersect those circles in point A, B, C, D respectively then, Prove that: Angle APB ≅ Angle CPD

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In the adjoining figure, BC is a diameter of a circle with center M. PA is a tangent at A from P which is a point on line BC. AO perpendicular to BC. PROVE THAT: DP² = BP x CP - BD x CD.

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In triangleABC, angle A is an obtuse angle. P is the circumcentre of triangleABC. Prove that anglePBC = angleA -90°

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In the adjoining figure, DE intersects the sides of triangle ABC in point P and Q such that, m(arc AD) = m(arc DB) and m(arc AE) = m(arc EC) SHOW THAT :- Angle PQC ≅ Angle BPQ

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