Bisector of angle B and angle C in △ABC meet each other at P. Line AP cuts the side BC at Q. Prove that: AP/PQ=(AB+AC)/BC. Get link Facebook X Pinterest Email Other Apps September 30, 2018 Get link Facebook X Pinterest Email Other Apps Comments
In △BAC, Angle BAC= 90°, segment AD, seg BE and seg CF are medians. Prove: 2(AD²+BE²+CF²)=3BC² September 30, 2018 Read more
In triangle ABC, Angle ACB=90°, seg CD is perpendicular to seg AB, seg DE is perpendicular to seg CD. Show that: CD² x AC = AD x AB x DE. September 30, 2018 Read more
Through the midpoint M of the side CD of parallelogram ABCD, the line BM is drawn intersecting AC in L and AD produced in E. Prove that EL=2BL. September 30, 2018 Read more
Comments
Post a Comment