From the same place at 7cm 'A' started walking in the north at the speed of 5km/hr. After 1 hour B started cycling in the east at a speed of 16km/hr. At what time they will be at distance of 52km apart from each other.
In the adjoining figure, AD is the bisector of the exterior angle A of triangle ABC. Seg AD intersects the side BC produced in D. Prove that: BD/CD=AB/AC.
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