In ▢ABCD points P, Q, R and S lies on sides AB, BC, CD and AD respectively such that seg PS is parallel to seg BD parallel to seg QR and seg PQ is parallel to seg SR. Then prove that seg PQ is parallel to seg AC.
In the adjoining figure, AD is the bisector of the exterior angle A of triangle ABC. Seg AD intersects the side BC produced in D. Prove that: BD/CD=AB/AC.
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