In the adjoining figure, AB is a diameter of a circle with center O, Seg AC is a tangent to the circle at point A. Line JD touches circle at point D, and intersects segment AC in point J. Prove that: seg AJ ≅ seg CJ
In the adjoining figure, AD is the bisector of the exterior angle A of triangle ABC. Seg AD intersects the side BC produced in D. Prove that: BD/CD=AB/AC.
Comments
Post a Comment