In the adjoining figure, BC is a diameter of a circle with center M. PA is a tangent at A from P which is a point on line BC. AO perpendicular to BC. PROVE THAT: DP² = BP x CP - BD x CD.
In the adjoining figure, AD is the bisector of the exterior angle A of triangle ABC. Seg AD intersects the side BC produced in D. Prove that: BD/CD=AB/AC.
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