In the adjoining figure, DE intersects the sides of triangle ABC in point P and Q such that, m(arc AD) = m(arc DB) and m(arc AE) = m(arc EC) SHOW THAT :- Angle PQC ≅ Angle BPQ
In △BAC, Angle BAC= 90°, segment AD, seg BE and seg CF are medians. Prove: 2(AD²+BE²+CF²)=3BC²
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