Point I is the incenter of △ ABC, Angle BIC=120°, BC=4cm, median AP=3cm. Draw △ABC. Get link Facebook X Pinterest Email Other Apps September 28, 2018 Get link Facebook X Pinterest Email Other Apps Comments
In the adjoining figure, AD is the bisector of the exterior angle A of triangle ABC. Seg AD intersects the side BC produced in D. Prove that: BD/CD=AB/AC. September 30, 2018 Read more
In △BAC, Angle BAC= 90°, segment AD, seg BE and seg CF are medians. Prove: 2(AD²+BE²+CF²)=3BC² September 30, 2018 Read more
If the sum of the roots of the quadratic equation ax²+bx+c=0 is equal to the sum of the squares of their reciprocals then, Prove that: 2a²c= c²b + b²a. September 30, 2018 Read more
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