Point O is the orthocenter of △ABC, m∠BOC=105°, seg AD is perpendicular to seg BC, BC=6.5cm and AD=3.5cm. Draw △ABC. Get link Facebook X Pinterest Email Other Apps September 28, 2018 Get link Facebook X Pinterest Email Other Apps Comments
In △BAC, Angle BAC= 90°, segment AD, seg BE and seg CF are medians. Prove: 2(AD²+BE²+CF²)=3BC² September 30, 2018 Read more
Through the midpoint M of the side CD of parallelogram ABCD, the line BM is drawn intersecting AC in L and AD produced in E. Prove that EL=2BL. September 30, 2018 Read more
In triangle ABC, Angle ACB=90°, seg CD is perpendicular to seg AB, seg DE is perpendicular to seg CD. Show that: CD² x AC = AD x AB x DE. September 30, 2018 Read more
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